16x^2-1212x+1024=0

Solution for 16x^2-1212x+1024=0 equation:

16x^2-1212x+1024=0

a = 16; b = -1212; c = +1024;
Δ = b2-4ac
Δ = -12122-4·16·1024
Δ = 1403408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1403408}=\sqrt{16*87713}=\sqrt{16}*\sqrt{87713}=4\sqrt{87713}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1212)-4\sqrt{87713}}{2*16}=\frac{1212-4\sqrt{87713}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1212)+4\sqrt{87713}}{2*16}=\frac{1212+4\sqrt{87713}}{32}
$